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.25x^2+.75x=0
a = .25; b = .75; c = 0;
Δ = b2-4ac
Δ = .752-4·.25·0
Δ = 0.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.75)-\sqrt{0.5625}}{2*.25}=\frac{-0.75-\sqrt{0.5625}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.75)+\sqrt{0.5625}}{2*.25}=\frac{-0.75+\sqrt{0.5625}}{0.5} $
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